1. ## Quadratics! need (more) help!

Find the value of k in 2kx^2+3x-3=0 if the discriminant is -39

thanks again.

$2kx^2+3x-3=0$

a = 2k, b = 3 , c = -3

Discriminant $= b^2-4ac=-39$

$(3)^2-4(2k)(-3)=-39$

$9+24k=-39$

Now, can you finish up???

3. Yup thanks man.