• Oct 26th 2008, 11:13 AM
Gigabytes
Find the value of k in 2kx^2+3x-3=0 if the discriminant is -39

thanks again.
• Oct 26th 2008, 11:17 AM
Shyam
$2kx^2+3x-3=0$

a = 2k, b = 3 , c = -3

Discriminant $= b^2-4ac=-39$

$(3)^2-4(2k)(-3)=-39$

$9+24k=-39$

Now, can you finish up???
• Oct 26th 2008, 11:24 AM
Gigabytes
Yup thanks man.