Hey! We are currently doing the quadratics section. I have this question on my assignment and im not quite sure how to do it. It is: Solve (x-1)(x+1)=-4(x+2) Also Solve 16+13 over x(x+1) = 0
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Originally Posted by Gigabytes Solve (x-1)(x+1)=-4(x+2) Open paranthesis, $\displaystyle x^2 - 1 = -4x - 8 \implies x^2 + 4x +7 = 0$ Now just quadradic formula.
Thanks!
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