Quadratics! need help!

Hey! We are currently doing the quadratics section. I have this question on my assignment and im not quite sure how to do it.

It is:

Solve (x-1)(x+1)=-4(x+2)


Also

Solve 16+13 over x(x+1) = 0

Quote:

---

Originally Posted by Gigabytes

Solve (x-1)(x+1)=-4(x+2)

---

Open paranthesis,
$\displaystyle x^2 - 1 = -4x - 8 \implies x^2 + 4x +7 = 0$

Now just quadradic formula.

Thanks!