|2x/3 + 5| ≥ 6
I cant figure out how to solve this one...I tried (im not sure if it's correct) andi couldnt finish it off.
Thankssss in advance :-)
okay thanks guys..
here i tried to solve it...i hope its correct...
|2x/3 + 5| ≥ 6
2x + 15 divided by 3 ≥ 6
2x + 5 ≥ 6
2x ≥ 6 - 5
x ≥ 1/2
or
|2x/3 + 5| ≥ -6
= x ≥ -11/2
gosh...why do i feel like its wrong?? anyhow please let me know if its correct or wrong thanks!
It is a question that tests your understanding of math. I dare you to ask it to your stupid physics teacher no way she can get it.
Did you try graphing them?
y=abs(x) and y=abx(x+1) and see where they interesect.
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The solution to that equation (and this is why I like it so much besides for it being my problem) is that,
-1<=x<=0
There are infinitely many solutions!
|2x/3+5| ≥ 6
I think it is important to remember:
|x| = x if x ≥ o
and
|x| = -x if x ≤ 0
So:
If 2x/3 + 5 ≥ 0, then:
2x/3+ 5 ≥ 6
And solve:
x ≥ 3/2
Now, if 2x/3 + 5 ≤ 0, then:
-(2x/3 + 5) ≥ 6
2x/3 + 5 ≤ -6
2x/3 ≤ -11
x ≤ -33/2