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Math Help - How to solve |2x/3 + 5| ≥ 6 ??

  1. #16
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    inequality

    i just sent a reply to this problem sent in by another.
    here is my answer

    2x/3 +5=>6
    2x/3 = 6-5=1
    x=3/2 values of x exceeding 3/2 result in the left side of the equation exceeding 6
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  2. #17
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    Quote Originally Posted by bjhopper View Post
    i just sent a reply to this problem sent in by another.
    here is my answer

    2x/3 +5=>6
    2x/3 = 6-5=1
    x=3/2 values of x exceeding 3/2 result in the left side of the equation exceeding 6
    As qspeechc already posted, this is only half the solution.

    -Dan
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  3. #18
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    I think I got it

    Quote Originally Posted by Cherry View Post
    |2x/3 + 5| ≥ 6


    I cant figure out how to solve this one...I tried (im not sure if it's correct) andi couldnt finish it off.

    Thankssss in advance :-)
    This is easy (I think)

    Ok so you set it up !2x + 5 > or equal to 6
    --
    3


    Multiply all sides by 3
    !2x + 15! > or equal to 18
    then you do
    2x + 15 > or equal to 18 or 2x + 15 < -18 subtract 15 from all sides

    2x + 15 > or equal to 18 or 2x + 15 < or equal to 18
    - 15 - 15 - 15 - 15

    You get 2x > or equal to 3 or 2x < or equal to - 33
    divide by 2. x > or equal to 1.5 or x< or equal to -16.5

    Now all you have to do is graph it.
    Last edited by Itachi888Uchiha; December 2nd 2007 at 08:22 PM. Reason: I messed up the math, but my formula is correct ( I think).
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  4. #19
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    Question How to solve |2x/3 + 5| ≥ 6 ??

    correct x=1,5 its means [1.5;+infinity)
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