# Thread: How to solve |2x/3 + 5| ≥ 6 ??

1. ## inequality

i just sent a reply to this problem sent in by another.

2x/3 +5=>6
2x/3 = 6-5=1
x=3/2 values of x exceeding 3/2 result in the left side of the equation exceeding 6

2. Originally Posted by bjhopper
i just sent a reply to this problem sent in by another.

2x/3 +5=>6
2x/3 = 6-5=1
x=3/2 values of x exceeding 3/2 result in the left side of the equation exceeding 6
As qspeechc already posted, this is only half the solution.

-Dan

3. ## I think I got it

Originally Posted by Cherry
|2x/3 + 5| ≥ 6

I cant figure out how to solve this one...I tried (im not sure if it's correct) andi couldnt finish it off.

This is easy (I think)

Ok so you set it up !2x + 5 > or equal to 6
--
3

Multiply all sides by 3
!2x + 15! > or equal to 18
then you do
2x + 15 > or equal to 18 or 2x + 15 < -18 subtract 15 from all sides

2x + 15 > or equal to 18 or 2x + 15 < or equal to 18
- 15 - 15 - 15 - 15

You get 2x > or equal to 3 or 2x < or equal to - 33
divide by 2. x > or equal to 1.5 or x< or equal to -16.5

Now all you have to do is graph it.

4. ## Question How to solve |2x/3 + 5| ≥ 6 ??

correct x=1,5 its means [1.5;+infinity)

Page 2 of 2 First 12