Pls solve a following dilemma

a=b

a^2=ab Multiplying both sides by a

a^2-b^2=ab-b^2 Subtracting b^2 from both sides

(a+b)(a-b)=b(a-b)

(a+b)=b

b+b=b

2b=b

2=1

Printable View

- Oct 25th 2008, 11:42 AMvaishaliingleSolve a dilemma
Pls solve a following dilemma

a=b

a^2=ab Multiplying both sides by a

a^2-b^2=ab-b^2 Subtracting b^2 from both sides

(a+b)(a-b)=b(a-b)

(a+b)=b

b+b=b

2b=b

2=1 - Oct 25th 2008, 11:45 AMgalactus
This is a cliche done to death. Look close. a=b, doesn't it?. Therefore, you have division by 0 and the proof is bad.