Thread: Solving Nonlinear equations

How would I turn m=2, b=-2 into y=mx+b.

Thank you for any help!

Originally Posted by largebabies

"Consider the equations y=10/x. x (not equal to sign) 0 y = mx+b, where m,b (Large e sign, not entirely sure what it is) R In each case the graph of y = 10/x is given. For each: - Write the equation in the form y= mx+b for the given values of m and b, - Sketch an appropriate line - State the number of solutions and write them as ordered pairs (to the nearest tenth where necessary)" So the equation I have is... "m = 2, b = -2 There's a graph with an x and a y axis as well but i'm sure you all know what that looks like. So in short, how would I turn m=2, b=-2 into y=mx+b. I can figure out the rest on my own. Thank you for any help!

I'd help but I've got no idea what you're asking.

Please use paragraphs when writing and use LaTeX to do mathematical symbols. There's a sub forum dedicated to LaTeX code...

I simplified it alot, most of it was pointless information anyways.

Originally Posted by largebabies

"Consider the equations and , where . In each case the graph of y = 10/x is given. For each: - Write the equation in the form y= mx+b for the given values of m and b, - Sketch an appropriate line - State the number of solutions and write them as ordered pairs (to the nearest tenth where necessary)" So the equation I have is... "m = 2, b = -2 There's a graph with an x and a y axis as well but i'm sure you all know what that looks like. So in short, how would I turn m=2, b=-2 into y=mx+b. I can figure out the rest on my own. Thank you for any help!

All you need to do is substitute these two values into the slope intercept form of a line:

since m=2 and b=-2, we see that is the equation of our line.

Now try to find [any] possible solutions to (this will give you the solutions). Then write the solutions of the ordered pair.

Here's the graph of those two functions over the interval :



Does this make sense?

--Chris