# Solving Nonlinear equations

• Oct 24th 2008, 07:36 PM
largebabies
Solving Nonlinear equations
How would I turn m=2, b=-2 into y=mx+b.

Thank you for any help! :)
• Oct 24th 2008, 07:42 PM
Prove It
Quote:

Originally Posted by largebabies
"Consider the equations y=10/x. x (not equal to sign) 0 y = mx+b, where m,b (Large e sign, not entirely sure what it is) R In each case the graph of y = 10/x is given. For each: - Write the equation in the form y= mx+b for the given values of m and b, - Sketch an appropriate line - State the number of solutions and write them as ordered pairs (to the nearest tenth where necessary)" So the equation I have is... "m = 2, b = -2 There's a graph with an x and a y axis as well but i'm sure you all know what that looks like. So in short, how would I turn m=2, b=-2 into y=mx+b. I can figure out the rest on my own. Thank you for any help! :)

I'd help but I've got no idea what you're asking.

Please use paragraphs when writing and use LaTeX to do mathematical symbols. There's a sub forum dedicated to LaTeX code...
• Oct 24th 2008, 08:03 PM
largebabies
I simplified it alot, most of it was pointless information anyways.
• Oct 24th 2008, 08:04 PM
Chris L T521
Quote:

Originally Posted by largebabies
"Consider the equations $y=\frac{10}{x},~~x\neq 0$ and $y = mx+b$, where $m,~b\in\mathbb{R}$. In each case the graph of y = 10/x is given. For each: - Write the equation in the form y= mx+b for the given values of m and b, - Sketch an appropriate line - State the number of solutions and write them as ordered pairs (to the nearest tenth where necessary)" So the equation I have is... "m = 2, b = -2 There's a graph with an x and a y axis as well but i'm sure you all know what that looks like. So in short, how would I turn m=2, b=-2 into y=mx+b. I can figure out the rest on my own. Thank you for any help! :)

All you need to do is substitute these two values into the slope intercept form of a line:

since m=2 and b=-2, we see that $y=2x-2$ is the equation of our line.

Now try to find [any] possible solutions to $\frac{10}{x}=2x-2$ (this will give you the solutions). Then write the solutions of the ordered pair.

Here's the graph of those two functions over the interval $\left[-3,4\right]$:

http://img.photobucket.com/albums/v4...521/prob-2.jpg

Does this make sense?

--Chris