What is the simplified numerical value of the sum:

$\displaystyle \log_{2} (1-\frac{1}{2}) + \log_{2} (1-\frac{1}{3}) + ... \log_{2} (1-\frac{1}{64})$

I'm not sure how to go about solving this problem.

Would it be

$\displaystyle \log_{2} ((1-\frac{1}{2})(1-\frac{1}{3}) etc)$

I can see how other properties of logs would apply as well, but I don't know the best way to go about this, and I'm not sure how to correctly arrive at a final answer