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Thread: Work Problem

  1. #1
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    Work Problem

    If 6J work is needed to stretch a spring from 10cm to 12cm and another 10J is needed to stretch it from 12 cm to 14 cm, what is the natural length?
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  2. #2
    Senior Member vincisonfire's Avatar
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    This is a physic problem I suggest you this forum Physics Help and Math Help - Physics Forums
    However,
     U = \frac{1}{2} k (x-x_0)^2
     U_1 = \frac{1}{2} k (10-x_0)^2
     U_2 = \frac{1}{2} k (12-x_0)^2
     U_2 - U_1 = 6 = \frac{1}{2} k [(12-x_0)^2 - (10-x_0)^2]
    Solve for k
    Replace k by what you found in
     U_4 - U_3 = 10 = \frac{1}{2} k [(14-x_0)^2 - (12-x_0)^2]
    and solve for  x_0
    Answer is 8.
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