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Math Help - Simplify

  1. #1
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    Simplify

    f= (ab 'cd ')+(a 'b 'cd) +(a 'bc 'd)+(a 'bcd)+(ab 'cd)+(abc 'd)

    Simplify the algebraic form for f as much as possible.
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  2. #2
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    Quote Originally Posted by captainjapan View Post
    f= (ab 'cd ')+(a 'b 'cd) +(a 'bc 'd)+(a 'bcd)+(ab 'cd)+(abc 'd)
    Simplify the algebraic form for f as much as possible.
    What do those symbols mean? What is f?
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  3. #3
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    Sorry here is a clarification.

    A B C D Output F
    0 0 0 0----0
    0 0 0 1----0
    0 0 1 0----1
    0 0 1 1----1
    0 1 0 0----0
    0 1 0 1----1
    0 1 1 0----0
    0 1 1 1----1
    1 0 0 0----0
    1 0 0 1----0
    1 0 1 0----0
    1 0 1 1----1
    1 1 0 0----0
    1 1 0 1----1
    1 1 1 0----0
    1 1 1 1----0

    Would this be correct as the algebraic expression?

    for output f the eg is f = (a.b.c.d)+(a.b.c.d) +(a.b.c.d)+(a.b.c.d)+(a.b.c.d)+(a.b.c.d)

    + = OR
    . = AND
    = NOT

    How do I simplify the algebraic form for f as much as possible?
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