Calculate the real part, the imaginary part, and the absolute value of the following expression:
i * [(1+2i)(5-3i)+3i/(1+i)].
So I did the math out this way:
i * [(4+21i)/(1+i)] = (4i-21)/(1+i)
Is this correct and what do you call the imaginary part and the real part if a denominator exists with an imaginary i?
Thanks for any help.
Sep 14th 2006, 02:41 PM
(1+2i)(5-3i)= 11+7i is correct!
You should then rewrite 3i/(1+i)= (3i)(1-i)/2 = (3+3i)/2
i[(11+7i)+ (3+3i)/2]=(-7+11i)+(-3+3i)/2 =(-17/2)+(25/2)i
Sep 14th 2006, 02:59 PM
I really appreciate the help Plato. I was going to ask how the second part worked but I figured it out. You just multiply it by its conjugate.
Sep 14th 2006, 03:07 PM
That really is an important point.
In general, we do not allow complex numbers written as 1/(a+bi).
In fact, the multiplicative inverse is, (a+bi)^(-1) = (a-bi)/(a^2+b^2).
That is the conjugate divided by the absolute value squared.