A little rusty on my exponent rules. Please help...thanks (2^a)^(b-1) = ? (2^a)(2^(ab-1)) = ?
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Originally Posted by noles2188 A little rusty on my exponent rules. Please help...thanks (2^a)^(b-1) = ? (2^a)(2^(ab-1)) = ? For the first one, recall that: $\displaystyle (x^a)^b=x^{ab}$ That would yield $\displaystyle (2^a)^{b-1}=2^{a(b-1)}=2^{ab-a}$ For the second one, recall that: $\displaystyle (x^a)(x^b)=x^{a+b}$ That would yield $\displaystyle (2^a)(2^{ab-1})=2^{a+ab-1}=2^{a(1+b)-1}$
noles... are you studying for mac1140 with dr.kutter exam 2 tomorrow?
no, i'm just doing some homework, and there were exponents, which i haven't done for a while
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