I'm not sure if I know how to write these out, but here goes: (multiply and simplify) k^2+11k+28 X k^2+8k k^2+12k+32 X k^2+4k-21 ADD and simplify: m^2-8m + 15 m-5 m-5 That is m^2-8m over m-5 PLUS 15 over m-5
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The first one (k^2+11k+28)(k^2+8k)=k^4+8k^3+11k^3+88k^2+28k^2+22 4k=k^4+19k^3+116k^2+224k That looks like it to me unless I messed up my mental math. Do you see the method?
Originally Posted by Jameson The first one (k^2+11k+28)(k^2+8k)=k^4+8k^3+11k^3+88k^2+28k^2+22 4k=k^4+19k^3+116k^2+224k That looks like it to me unless I messed up my mental math. Do you see the method? Not really, but I'm a bit dense tonite. My answer was nowhere near that. I think I will go beddy-bye. It is 12:03 a.m. here. My eyes are soooo tired Thanks. Bye.
Originally Posted by Suwanee ADD and simplify: m^2-8m + 15 m-5 m-5 Both fractions have the same denominator, so you can just add the numerators: (m^2 - 8m + 15)/(m - 5) Now, the numerator factors: m^2 - 8m + 15 = (m-5)(m-3), so we get [(m-5)(m-3)]/(m-5) = m - 3 because the m-5 terms cancel. -Dan
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