This is the problem. A number is 42 less than its square. Find all such numbers. Can you please tell me how to do this? what steps to follow. Thanks.
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Originally Posted by Suwanee This is the problem. A number is 42 less than its square. Find all such numbers. Can you please tell me how to do this? what steps to follow. Thanks. x=x^2-42 Thus, x^2-x-42=0 Thus, (x-7)(x+6)=0
thank you.
Originally Posted by Suwanee thank you. Keep this up and you'll have more posts than Quick before too long. -Dan