Results 1 to 3 of 3

Math Help - Logarithm qsn :D

  1. #1
    Junior Member
    Joined
    Mar 2008
    Posts
    30

    Logarithm qsn :D

    Hi all!

    Just wondering whether i could get some help solving this question for "t"? Do you have to put log10 on each side? Step by step if possible would be greatly appreciated.

    20(10^0.1t) = 25(10^0.05t)


    Cheers
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Member
    Joined
    Oct 2008
    Posts
    88
    I would divide both sides by 20, then divide both sides by  10^{0.05t} .
    You can use index laws to simplify your exponents.

    Then I would take a log of both sides.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor
    Prove It's Avatar
    Joined
    Aug 2008
    Posts
    10,969
    Thanks
    1010
    Quote Originally Posted by steph_r View Post
    Hi all!

    Just wondering whether i could get some help solving this question for "t"? Do you have to put log10 on each side? Step by step if possible would be greatly appreciated.

    20(10^0.1t) = 25(10^0.05t)


    Cheers
    20\left(10^{0.1t}\right) = 25\left(10^{0.05t}\right)

    \frac{\left(10^{0.1t}\right)}{\left(10^{0.05t}\rig  ht)} = \frac{25}{20}

    10^{0.1t - 0.05t} = \frac{5}{4}

    10^{0.05t} = \frac{5}{4}

    0.05t = \log_{10}{\frac{5}{4}}

    t = 20\log_{10}{\frac{5}{4}}
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 3
    Last Post: July 18th 2011, 07:04 AM
  2. logarithm
    Posted in the Algebra Forum
    Replies: 3
    Last Post: July 17th 2010, 04:23 AM
  3. Logarithm #2
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: June 1st 2010, 05:29 AM
  4. Logarithm
    Posted in the Algebra Forum
    Replies: 6
    Last Post: September 17th 2009, 10:23 PM
  5. Logarithm
    Posted in the Algebra Forum
    Replies: 4
    Last Post: March 13th 2008, 10:05 AM

Search Tags


/mathhelpforum @mathhelpforum