Ok I am confused with these problems:
Solving for X and Y using substitution:
1. 2x+y=4
3x-y=6
2. 3x+15y=3
2x-5y=-28
3. 4x-5y=0
8x-10y+15
Solving for X and Y using linear addition:
4.5x-7y=2
3x=4y
5.10x+10y=40-5x
9x+2y=32-6y
6. 2x=8y+24
3x+5y=2
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Ok I am confused with these problems:
Solving for X and Y using substitution:
1. 2x+y=4
3x-y=6
2. 3x+15y=3
2x-5y=-28
3. 4x-5y=0
8x-10y+15
Solving for X and Y using linear addition:
4.5x-7y=2
3x=4y
5.10x+10y=40-5x
9x+2y=32-6y
6. 2x=8y+24
3x+5y=2
You have two equations and two unknowns. Start with the first equation: 2x+y=4. Solve for y.Quote:
Originally Posted by peachgal
2x+y=4
y=4-2x
Now take this and plug in "4-2x" for "y" in the second equation.
3x-y=6
3x-(4-2x)=6
3x-4+2x=6
5x-4=6
5x=10
x=2
Now that we have found x, plug "2" in for "x" in either the first or second equation to find y.
2x+y=4
2(2)+y=4
4+y=4
y=0
So the final answer is x=0, y=2. If you plug in these numbers to both equations you can verify they are correct.