Could anyone please solve these quadratic equations real quickly please?
1. (x+1)(x+2)
2. (x+2)(x-1)
3. (x-1)(x-2)
4. (x+3)(x-3)
5. (x-7)squared
6. xsquared + 4x + 3
7. xsquared + 7x + 12
8. xsquared - 5x + 4
9. xsquared + 21x + 20
10. xsquared + 2x - 15
11. xsquared - x - 12
12. xsquared + 5x - 36
I guess I'm confused now about what you want to accomplish. In your last post, all you did was multiply the two binomials together. And, I might add, you had a little problem with that.
So, let me ask this. For the first 5, do you just want to multiply these binomials together? Or do you want to set them = 0 and solve for x?
{1}
or
And for 6-12, do you just want to factor them or set them = 0 and solve for x?
I am not too sure how to answer what you asked really.
The easiest way I could put it is that I want the answers for 1-4 to look like the questions for 6-12 and vice versa.
So that would basically be the first example you said.
I hope that makes it clearer for you.
Ok, I got it now. You just want to multiply these binomials together in 1-5 and factor 6-12.
I will demonstrate a technique for 1-5 using #1.
We are going to expand this rascal using the distributive property. The general form is this:
Specifically for #1, we have:
Now work the other 4 just like that.
For 6-12, we need to factor the trinomial (3 term expression) into the product of two binomals (2 term expressions).
We'll use #6
Now this is where you have to use your head a little. You must think of a pair of numbers whose product is 3 and whose sum is 4. The 3 comes from the last term in the trinomial, and the 4 comes from the middle term.
How many ways can you multiply two whole numbers to get 3? Remember their sum must be 4.
3 X 1 = 3
3 + 1 = 4
So, the numbers must be 3 and 1.
Now you try some.