# Math Help - log !

1. ## log !

-4/3
(64)

2. Originally Posted by mak15
-4/3
(64)
Question makes no sense.
What doth thee wish?

3. Hello, mak15!

This doesn't involve logs . . .

$64^{-\frac{4}{3}}$

You're expected to know the basics of rational and negative exponents . . .

$64^{-\frac{4}{3}} \;=\;\frac{1}{64^{\frac{4}{3}}} \;=\;\frac{1}{(\sqrt[3]{64})^4} \;=\;\frac{1}{4^4} \;=\;\frac{1}{256}$