Prove that if one root of is rational, then both are rational.
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You know that solution of a quadratic equation follows the quadratic formula. Then assume that one of the roots is rational, and not complex, so sqrt(b^2-4ac) is a rational number. Then show that the other root must also be rational.
if is rational then both root are rational.
How do I show that the other root is rational?
Originally Posted by megster_567 Prove that if one root of is rational, then both are rational. One root of this equation is now if that is rational then what does the other root, mean?
Originally Posted by Plato One root of this equation is now if that is rational then what does the other root, mean? I think I got that, I'm just not sure how to incorporate it into a proof...
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