Most important for me is the result as I made this exercise and my result is different as given in the book.

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- October 19th 2008, 05:51 AMachacyLogarithmic inequality

Most important for me is the result as I made this exercise and my result is different as given in the book. - October 19th 2008, 07:12 AMSoroban
Hello, achacy!

I have a somewhat intricate solution.

. . Maybe someone can do better . . .

Quote:

.[1]

I converted the terms to the same base.

. . Take logs: .

. .

. . Hence: . .[2]

From the Base-Change Formula: . .[3]

Substitute [2] and [3] into [1]: .

We have: .

Let

Muliply by . . . assuming

Multiply by 2: .

There are two cases:

. .

. .

Then we have: .

Multiply by

Therefore: .

- October 19th 2008, 07:26 AMsosgfput y = lnx/ln3 ===> -y > 1/y - 5/2

2y^2 -5y + 2 < 0 ===> 1/2< y < 2 ===> rotsq( 3) < x < 9