log(base)4(32)
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re-write it as $\displaystyle log_4 64 - log_4 2 $
Originally Posted by mak15 log(base)4(32) Alternatively: $\displaystyle \log_4 32 = x \Rightarrow 4^x = 32 \Rightarrow 2^{2x} = 2^5 \, ....$
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