1. ## log

1/log 25
25 what's its value?

2. base e?

3. it's like 25 at the base 1/log 25

4. so like: $\frac{1}{Log_{25} 25}$ ?

Well what do you know about $Log_x x = y$
It's the same as: $x^y = x$ which implies x = 1.

5. Originally Posted by franckherve1
it's like 25 at the base 1/log 25
Does it look like this

$\frac{1}{\log{25}}$

6. it's like 25 with exponent 1/log 25

7. Originally Posted by franckherve1
it's like 25 with exponent 1/log 25
do like U-god said then

so it simplfies to 1

8. but the base is not 25 ...there's nothing so i guess the base should be 10

9. In my country if there's no base, the base is taken to be e. But I'm aware that in other countries it's taken to be 10.

If it was 10 the answer would be $\frac{1}{1.398}$

However if it was e, the answer would be $\frac{1}{3.219}$

to 3 decimal places.

10. Originally Posted by franckherve1
but the base is not 25 ...there's nothing so i guess the base should be 10
so it is

$\frac{1}{\log{25^{25}}}$

1
10
25
125

1
10
25
125

13. I think 125 but I'm still confused as to how the prob looks like

14. it might be true but the question is how?

15. Originally Posted by franckherve1
1/log 25
25 what's its value?
Do you mean:

$25^{1/\log(25)}$

If so, let the base be $b$ then:

$25^{1/\log(25)}=(b^{\log(25)})^{1/\log(25)}=b$

CB

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