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Math Help - log

  1. #1
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    log

    1/log 25
    25 what's its value?
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  2. #2
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    base e?
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  3. #3
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    it's like 25 at the base 1/log 25
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  4. #4
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    so like:  \frac{1}{Log_{25} 25} ?

    Well what do you know about  Log_x x = y
    It's the same as:  x^y = x which implies x = 1.
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  5. #5
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    Quote Originally Posted by franckherve1 View Post
    it's like 25 at the base 1/log 25
    Does it look like this

    \frac{1}{\log{25}}
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  6. #6
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    it's like 25 with exponent 1/log 25
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  7. #7
    Super Member 11rdc11's Avatar
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    Quote Originally Posted by franckherve1 View Post
    it's like 25 with exponent 1/log 25
    do like U-god said then

    so it simplfies to 1
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  8. #8
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    but the base is not 25 ...there's nothing so i guess the base should be 10
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  9. #9
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    In my country if there's no base, the base is taken to be e. But I'm aware that in other countries it's taken to be 10.

    If it was 10 the answer would be \frac{1}{1.398}

    However if it was e, the answer would be  \frac{1}{3.219}

    to 3 decimal places.
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  10. #10
    Super Member 11rdc11's Avatar
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    Quote Originally Posted by franckherve1 View Post
    but the base is not 25 ...there's nothing so i guess the base should be 10
    so it is

    \frac{1}{\log{25^{25}}}
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  11. #11
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    there are four answers
    1
    10
    25
    125
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  12. #12
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    there are four answers
    1
    10
    25
    125
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  13. #13
    Super Member 11rdc11's Avatar
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    I think 125 but I'm still confused as to how the prob looks like
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  14. #14
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    it might be true but the question is how?
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  15. #15
    Grand Panjandrum
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    Quote Originally Posted by franckherve1 View Post
    1/log 25
    25 what's its value?
    Do you mean:

    25^{1/\log(25)}

    If so, let the base be b then:

    25^{1/\log(25)}=(b^{\log(25)})^{1/\log(25)}=b

    CB
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