25^(1/log(25))=x

log[25^(1/log(25))]=log[x]

log(25)*1/log(25)=log[x]

1=log[x]

base (10 e or whatever) = x

Results 16 to 19 of 19

- Oct 19th 2008, 02:22 AM #16

- Joined
- Sep 2007
- Posts
- 66

- Oct 19th 2008, 05:30 AM #17

- Oct 19th 2008, 07:00 AM #18

- Joined
- Sep 2007
- Posts
- 66

- Oct 19th 2008, 07:38 AM #19