25^(1/log(25))=x

log[25^(1/log(25))]=log[x]

log(25)*1/log(25)=log[x]

1=log[x]

base (10 e or whatever) = x

Results 16 to 19 of 19

- October 19th 2008, 02:22 AM #16

- Joined
- Sep 2007
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- October 19th 2008, 05:30 AM #17

- October 19th 2008, 07:00 AM #18

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- Sep 2007
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- October 19th 2008, 07:38 AM #19