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Thread: Logarithm Urgent

  1. October 16th 2008, 12:03 AM #1
    manutd4life
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    Logarithm Urgent

    Solve, correct to 3 significant figures, the equation
    e^x + e^2x = e^3x
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  2. October 16th 2008, 12:31 AM #2
    Peritus
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    \begin{gathered}<br /> e^x \left( {e^{2x} - e^x - 1} \right) = 0 \hfill \\<br /> z \equiv e^x \hfill \\<br /> \Rightarrow z\left( {z^2 - z - 1} \right) = 0 \hfill \\ <br /> \end{gathered}

    now solve the quadratic equation and back substitute for x.
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