# Logarithm Urgent

• October 16th 2008, 12:03 AM
manutd4life
Logarithm Urgent
Solve, correct to 3 significant figures, the equation
e^x + e^2x = e^3x
• October 16th 2008, 12:31 AM
Peritus
$\begin{gathered}
e^x \left( {e^{2x} - e^x - 1} \right) = 0 \hfill \\
z \equiv e^x \hfill \\
\Rightarrow z\left( {z^2 - z - 1} \right) = 0 \hfill \\
\end{gathered}$

now solve the quadratic equation and back substitute for x.