I just attached an image of the question because I was having trouble showing exponents in text.
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Hello, schoolboydj! $\displaystyle 4^{2x^2+2x} \;=\;\boxed{(2^2)^{2x^2+2x} \;=\;2^{(2)(2x^2+2x)}} \;=\;2^{4x^2+4x} $ It's from this rule: .$\displaystyle (x^a)^b \:=\:x^{ab} $
In the boxed (red) line, you forgot to write the 2 before the x^2. Otherwise, everything in your solution is fine.
Thank you.
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