Hello Van:
For the first exercise, complete the square.
(p, q) are the coordinates of the vertex, by the way.
For the second exercise, I regret that I do not understand [tex]x[squared]. Is this some sort of multiplication?
Cheers,
~ Mark
Just click on the expression and it will show you the code used to make it.
1a) I think you just need to 'complete the square'. Are you familiar with this technique?
1b) Are you trying to find the minimum value of the parabola?
Use using the standard form of the parabola:
This will give you the x-coordinate of the vertex. You want to find the y-coordinate of the vertex, so substitute the x-coordinate into your original equation to solve for y.
This will be a minimum value since the parabola opens upward.
Now find f(6) in
Thanks very much so far guys, i'm stuck again though
2(b) Sketch the Graph of Stating the co-ordinates of the vertex.
I know its either a U or n shape, and the vertex is the extreme point on the curve, but i'm not sure how exactly to do it.
3(b) Find the constants a, b and c such that for all values of x
I know i asked a similar question already, but i'm stumped
Complete the square, complete the square, complete the square ...
Did you understand my first post when I told you that (p, q) are the coordinates of the vertex?
In other words, after you complete the square, you can immediately plot the vertex point.
You can see the y-intercept by simply inspecting the original equation, so you can immediately plot that point without doing any algebra at all.
After completing the square on this exercise, the two x-intercepts are found quite easily by setting y equal to zero and solving for x. (i.e., there's no need to use the quadratic formula.)
Plot those two points, and you've got four points plotted.
Sketch the right half of the parabola from the vertex through the rightmost x-intercept and up through the y-intercept.
Use symmetry, along with the other x-intercept, to sketch the left half.
You're done!
(By the way, when the leading coefficient is positive in a quadratic equation, then the parabola opens upward, and when the leading coefficient is negative, then the parabola opens downward.)
On your second exercise, do you recognize that the right side is the form that you get after completing the square?
In other words, complete the square on that exercise also, and you can then immediately read off the values of a, b, and c.
NOTE: Whoever authored that exercise should have stuck with the symbols p and q (or anything other than b and c) because the symbols b and c are NOT the same as the coefficients in the familiar ax^2 + bx + c form. Instead, the b and c are the coordinates of the vertex: (b,c). I think using b and c is quite potentially confusing. The symbol a is actually the leading coefficient, though.
Let us know if you need help completing the square on the second exercise. Remember to factor out the leading coefficient before you start. (Did you check out any lessons or examples?)
Cheers,
~ Mark