Find the 4th term of (x-3)8 (to the 8th power).
This is all I have for the question. Is this enough info to work this problem?
Thanks in advance.
Chu
There is a debate as to how one numbers the terms in a binominal expansion.
So much so, that in the US we have pretty much agreed not to use that terminology in contest questions.
But given you options, it is clear that Mr.F is correct you need to use the descending option.
$\displaystyle \left( {x - 3} \right)^8 = \sum\limits_{k = 0}^8 { {8 \choose k} x^{8 - k} \left( { - 3} \right)^k }$ so $\displaystyle k = 3$ give the term.
So the answer is either a or b.