Another Problem - split from "completing square"

**ThePerfectHacker** · September 8th 2006, 09:22 AM

Originally Posted by danielwu

$ x = -b \pm \sqrt \frac{b^2 - 4ac}{2a} $

I told you that formula is wrong.
If that is exactly what your book says then it wrong and you should burn it to death.

**danielwu** · September 8th 2006, 09:30 AM

Originally Posted by ThePerfectHacker

Multiply by 8h to get,
$8hr=b^2+4h^2$
Thus,
$4h^2-8hr+b^2=0$
Thus,
$a=5,b=-8h,c=b^2$

supposely i should take the coefficient right?

$ 4h^2-8rh+b^2=0 $
a = 4, b = -8 , c = 1

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{8\pm \sqrt{64 - 16}}{8}$

Am i right? pls correct me if i am wrong. thanks guys

**CaptainBlack** · September 8th 2006, 09:30 AM

Originally Posted by ThePerfectHacker

I told you that formula is wrong.
If that is exactly what your book says then it wrong and you should burn it to death.

If true burning to death is a too merciful fate for it. It should be extinguished
while still alive, be disembowelled, have its entrails burnt before its eyes, the
be hung on London Bridge until it smells so badly that the Aldermen demand
that it be taken down and disposed of somewhere where nobody will notice
(Utah?).

RonL

**ThePerfectHacker** · September 8th 2006, 09:33 AM

Originally Posted by danielwu

Am i right? pls correct me if i am wrong. thanks guys

Wrong.
For the third time the formula is,
$\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

**CaptainBlack** · September 8th 2006, 09:33 AM

Originally Posted by danielwu

supposely i should take the coefficient right?

$ 4h^2-8rh+b^2=0 $
a = 4, b = -8 , c = 1

$-(-8)\pm \sqrt \frac{(-8)^2 - 4(4)(1)}{2(4)}$

$8\pm \sqrt \frac{64 - 16}{8}$

Am i right? pls correct me if i am wrong. thanks guys

I expect ImPerfectHacker is composing a blistering reply to this
so I will just say, people have told you repeatedly that this is not the
quadratic formula.

RonL

**ThePerfectHacker** · September 8th 2006, 09:35 AM

Originally Posted by CaptainBlank

I expect ThePerfectHacker is composing a blistering reply to this
so I will just say, people have told you repeatedly that this is not the
quadratic formula.

RonL

It was a LaTeX error. The user does not know how to type that correctly. I presume it is because of the double bracket. I know that because I am speaking with the user through MSN.

**ThePerfectHacker** · September 8th 2006, 09:39 AM

Your new updated post is now correct.

**topsquark** · September 8th 2006, 10:19 AM

Originally Posted by CaptainBlack

If true burning to death is a too merciful fate for it. It should be extinguished
while still alive, be disembowelled, have its entrails burnt before its eyes, the
be hung on London Bridge until it smells so badly that the Aldermen demand
that it be taken down and disposed of somewhere where nobody will notice
(Utah?).

RonL

CaptainBlack I want you to know that I like women but, you know, I'm kinda getting turned on by this...

However, you forgot about smearing it in honey and burying it in a mound of fire ants, so don't expect any dates.

-Dan

**dan** · September 8th 2006, 12:05 PM

reading this thread gave me the best laugh i've had in a while...

^_^

$\sqrt[iel]{~dan}$

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