Hi there,
here is a question with a negative exponent on the bottom. I would appreciate ANY!! help!
Simplify.
x^2a-h x x^a-3h / (x^3a+h) ^-2
THANK YOU!
^ means exponent
You have,Originally Posted by notaveragejoe
$\displaystyle \frac{x^2 a-hx x^a-3h}{(x^3a+h)^{-2}}$
Since you are dividing by a negative exponent you can bring the denominator to the numerator and remove the negative,
$\displaystyle (x^2a-hx x^a-3h)(x^2a+h)^2$
Are you saying: $\displaystyle \frac{x^{2a-h}\times x^{a-3h}}{\left(x^{3a+h}\right)^{-2}}$Originally Posted by notaveragejoe
or: $\displaystyle \frac{\left(x^{2a}-h\right)\times \left(x^{a}-3h\right)}{\left(x^{3a}+h\right)^{-2}}$
if it's neither of those two than try rewriting it with as many paranthesis as possible and write out the word "times".