I have ln[1/sqrt(x)] I
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You can write $\displaystyle \frac{1}{\sqrt{x}}$ as $\displaystyle x^{-1/2}$.
ok. how would it be simplified into -.5ln[x] though?
Originally Posted by Shadowfox1 I have ln[1/sqrt(x)] I $\displaystyle \ln \frac{1}{\sqrt{x}} = \ln \frac{1}{x^{\frac{1}{2}}}= \ln x^{-\frac{1}{2}}= -\frac{1}{2} \ln x = -\frac{\ln x}{2}$
o ok. that makes sense. So can I always bring down the exponent when its negative?
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