# Math Help - fraction exponent in denominator

1. ## fraction exponent in denominator

I have ln[1/sqrt(x)]

I

2. You can write $\frac{1}{\sqrt{x}}$ as $x^{-1/2}$.

3. ok. how would it be simplified into -.5ln[x] though?

$\ln \frac{1}{\sqrt{x}} = \ln \frac{1}{x^{\frac{1}{2}}}= \ln x^{-\frac{1}{2}}= -\frac{1}{2} \ln x = -\frac{\ln x}{2}$