1. ## Indicies

$2^{2x+1}=2^{2x}\times2^{1}=4^{x2}$ Is that right?

2. Originally Posted by Flexible
$2^{2x+1}=2^{2x}\times2^{1}=4^{x2}$ Is that right?
No, that is not correct.

$2^{2x+1}=2^{2x} \cdot 2^1$ is true. This cannot be simplified further.

$2^{2x} \cdot 2 \neq 4^{2x}$

Remember the rule for multiplying same bases:

$x^a \cdot x^b=x^{a+b}$

Example: $2 \cdot 2^2 \neq 4^2$

$2 \cdot 2^2 = 2^3 = 8$

3. However, you can write $2^{2x+1}$ as $2 \cdot 4^x$.