# Indicies

• October 14th 2008, 11:45 AM
Flexible
Indicies
$2^{2x+1}=2^{2x}\times2^{1}=4^{x2}$ Is that right?
• October 14th 2008, 12:02 PM
masters
Quote:

Originally Posted by Flexible
$2^{2x+1}=2^{2x}\times2^{1}=4^{x2}$ Is that right?

No, that is not correct.

$2^{2x+1}=2^{2x} \cdot 2^1$ is true. This cannot be simplified further.

$2^{2x} \cdot 2 \neq 4^{2x}$

Remember the rule for multiplying same bases:

$x^a \cdot x^b=x^{a+b}$

Example: $2 \cdot 2^2 \neq 4^2$

$2 \cdot 2^2 = 2^3 = 8$
• October 14th 2008, 12:13 PM
icemanfan
However, you can write $2^{2x+1}$ as $2 \cdot 4^x$.