Could someone help with this please...
Hello, need help!
I assume that we're supposed to simplify the fraction . . .
We are expected to know how to factor and cancel . . .$\displaystyle \frac{8x^2 + 24x}{2x^2+5x-3}$
Factor: .$\displaystyle \frac{8x^2+24x}{2x^2+5x-3} \;=\;\frac{8x(x+3)}{(2x-1)(x+3)}$
Cancel: .$\displaystyle \frac{8x({\color{red}\rlap{/////}}x+3)}{(2x-1)({\color{red}\rlap{/////}}x+3)} \;=\;\frac{8x}{2x-1} $