$\displaystyle 3^{4-3x}=4^{x+5}$

$\displaystyle 4log3 - 3xlog3 = xlog4 + 5log4$

$\displaystyle -3xlog3 - xlog4 = 5log4 - 4log3$

$\displaystyle x(-3log3 - log4) = 5log4 - 4log3$

$\displaystyle x = \frac{5log4 - 4log3}{(-3log3 - log4)}$

My answer is completely wrong, apparently it's -0.542 so i guess theres something up with my factorising?