I have no idea how to do this could you please provide the steps to solving?
use the rational root theorem to list the possible roots and actual roots
x^4-2x^3-4x^2+11x-6
$\displaystyle x= \pm~\frac{p}{q}$
p ia an interger factor of the constant term
q is an interger factor of the leading coefficient
$\displaystyle x^4-2x^3-4x^2+11x-6$
so p is 6 and q is 1
so now factor out 6 and 1
Factors of 6 are $\displaystyle 1,2,3,6$
so $\displaystyle \pm~\frac{1,2,3,6}{1}$
so your possible roots are $\displaystyle 1,-1,2,-2,3,-3,6,-6$
Now use syntheic division aand try out your roots.
1 and 2 works out nicely
$\displaystyle (x-2)(x-1)(x^2+x-3)$