# Math Help - Logarithm

1. ## Logarithm

How would I solve this?

2^2x - 2^(x+1) = 0

Having trouble with this too

2^2x - 12 * 2^x + 32 = 0

2. $2^{2x}=2^{x+1}$

$2x=x+1$

$x=1$

3. For second one

$(2^x - 8)(2^x - 4) = 0$

$2^x =8$ gives $x=3$

$2^x =4$ gives $x=2$

4. Thanks Glaysher!