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Math Help - Logarithm

  1. #1
    Member classicstrings's Avatar
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    Logarithm

    How would I solve this?

    2^2x - 2^(x+1) = 0

    Having trouble with this too

    2^2x - 12 * 2^x + 32 = 0
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  2. #2
    Member Glaysher's Avatar
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    2^{2x}=2^{x+1}

    2x=x+1

    x=1
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  3. #3
    Member Glaysher's Avatar
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    For second one

    (2^x - 8)(2^x - 4) = 0

    2^x =8 gives x=3

    2^x =4 gives x=2
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  4. #4
    Member classicstrings's Avatar
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    Thanks Glaysher!
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