# Math Help - Solving equations

1. ## Solving equations

Hi, I need some help on this problem.

$\frac{2x^3-3x^3+x+1}{2x^3-3x^2-x-1} = \frac{3x^3-x^2+5x-13}{3x^3-x^3-5x+13}$

Thanks

For sure, 0 is a solution. If the problem tells you how much solutions you may be done!

3. Originally Posted by chaos787
Hi, I need some help on this problem.

$\frac{2x^3-3x^3+x+1}{2x^3-3x^2-x-1} = \frac{3x^3-x^2+5x-13}{3x^3-x^3-5x+13}$

Thanks
start by cross-multiplying: $\frac ab = \frac cd \Longleftrightarrow ad = bc$

you can try factorizing first using the rational roots theorem and long division, but i doubt these can be factored. so try if you want, but you may end up having to go with my first suggestion