Hi, I need some help on this problem.
$\displaystyle \frac{2x^3-3x^3+x+1}{2x^3-3x^2-x-1} = \frac{3x^3-x^2+5x-13}{3x^3-x^3-5x+13} $
Thanks
start by cross-multiplying: $\displaystyle \frac ab = \frac cd \Longleftrightarrow ad = bc$
you can try factorizing first using the rational roots theorem and long division, but i doubt these can be factored. so try if you want, but you may end up having to go with my first suggestion