1. ## Roots of quadratic equation

Please teach me how to do part b(iii).

2. Originally Posted by maybeline9216
Please teach me how to do part b(iii).
note that $(\alpha - \beta)^2 = \alpha^2 - 2 \alpha \beta + \beta^2$. with this, you can find $\alpha - \beta$ by square rooting both sides.

but how to find $\alpha^2 - 2 \alpha \beta + \beta^2$?

note that $(\alpha + \beta)^2 = \alpha^2 + 2 \alpha \beta + \beta^2$

$\Rightarrow (\alpha + \beta)^2 - 4 \alpha \beta = \color{red}\alpha^2 - 2 \alpha \beta + \beta^2$

and you know $\alpha + \beta$ as well as $\alpha \beta$ from part b(i)

3. Originally Posted by maybeline9216
Please teach me how to do part b(iii).
lets assume we are going to do this without using the quadratic formula.

$(\alpha-\beta)^2=\alpha^2+\beta^2-2\alpha \beta=(\alpha+\beta)^2-4\alpha \beta$

so:

$\alpha-\beta=\sqrt{(\alpha+\beta)^2-4\alpha \beta}$

and we know that $\alpha+\beta=k=7$ and that $\alpha \beta=2k-3=11$

CB