Using the graphical method I find an initial estimate for the solutionOriginally Posted by CaptainBlack
is x=2.36, y=1.64, and there is probably but one real solution.
RonL
Plot a graph of the curve represented by:Originally Posted by dan
$\displaystyle
x^2 +y^3 =10
$,
and on the same axes plot the graph the curve represented by:
$\displaystyle
x^3 -y^4 =-6
$.
The points where these curves cross are roots of the system.
RonL