14^log14 of 21

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- Oct 12th 2008, 05:37 PMlmschneiderLogarithms
14^log14 of 21

- Oct 12th 2008, 05:43 PMJhevon
- Oct 12th 2008, 05:45 PMlmschneider
Do you happen to know what that rule is called?

- Oct 12th 2008, 05:46 PMJhevon
- Oct 12th 2008, 05:48 PMlmschneider
I looked and it's not, but that's okay. I will keep looking. So the answer is 21 then?

- Oct 12th 2008, 06:06 PMJhevon
yes

it is not hard to prove though. i will show you how to prove it. that way, if you are not allowed to use this rule, this is how you would attempt the problem in general.

Let , we will show that

...........................................take to the base of both sides

.................since

...............................since

..............................................by taking the antilog of both sides.