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Math Help - integers, expanding & algebra

  1. #1
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    Exclamation integers, expanding & algebra

    ok, i have no idea how to do these complex questions

    like this: 4(y+2)-5(y+1)=y-1
    i dont know what steps to do, like should i do like-terms before SAMDEB or this, or that blah blah blah

    if some one could please show all steps for this question, i might be able to get it

    (BTW, this is grade nine math)
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  2. #2
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    Quote Originally Posted by Arexsis View Post
    ok, i have no idea how to do these complex questions

    like this: 4(y+2)-5(y+1)=y-1
    i dont know what steps to do, like should i do like-terms before SAMDEB or this, or that blah blah blah

    if some one could please show all steps for this question, i might be able to get it

    (BTW, this is grade nine math)

    Distribute the 4: 4y+8
    Distribute the -5: -5y-1

    resulting in: 4y+8-5y-1 = y-1,
    Now combine like terms, solving for y.
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  3. #3
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    resulting in: 4y+8-"5y-1" = y-1

    -5y-1... i think it's -5y-5 isn't it?
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  4. #4
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    i've now got a new problem

    after i did like terms i did SAMDEB and i got -Y=Y-4 what do i do now?(and the final answer is supposed to be 2)
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  5. #5
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    Quote Originally Posted by Arexsis View Post
    i've now got a new problem

    after i did like terms i did SAMDEB and i got -Y=Y-4 what do i do now?(and the final answer is supposed to be 2)
    I don't know what SAMDEB means...but

    subtract Y from both sides resulting in: -2Y = -4
    divide both sides by 2 gives you: y = 2
    Last edited by dolphinlover; October 12th 2008 at 04:51 PM. Reason: divide both sides by -2....sorry
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  6. #6
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    THANK YOU SO MUCH! (and SAMDEB is BEDMAS backwards, you use it for these kind of questions (expand first subtract and add second multiply and divide third and do brackets and exponents last)
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  7. #7
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    Quote Originally Posted by Arexsis View Post
    resulting in: 4y+8-"5y-1" = y-1

    -5y-1... i think it's -5y-5 isn't it?

    Yes it would be -5y-5.
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