# Math Help - integers, expanding & algebra

1. ## integers, expanding & algebra

ok, i have no idea how to do these complex questions

like this: 4(y+2)-5(y+1)=y-1
i dont know what steps to do, like should i do like-terms before SAMDEB or this, or that blah blah blah

if some one could please show all steps for this question, i might be able to get it

(BTW, this is grade nine math)

2. Originally Posted by Arexsis
ok, i have no idea how to do these complex questions

like this: 4(y+2)-5(y+1)=y-1
i dont know what steps to do, like should i do like-terms before SAMDEB or this, or that blah blah blah

if some one could please show all steps for this question, i might be able to get it

(BTW, this is grade nine math)

Distribute the 4: 4y+8
Distribute the -5: -5y-1

resulting in: 4y+8-5y-1 = y-1,
Now combine like terms, solving for y.

3. resulting in: 4y+8-"5y-1" = y-1

-5y-1... i think it's -5y-5 isn't it?

4. i've now got a new problem

after i did like terms i did SAMDEB and i got -Y=Y-4 what do i do now?(and the final answer is supposed to be 2)

5. Originally Posted by Arexsis
i've now got a new problem

after i did like terms i did SAMDEB and i got -Y=Y-4 what do i do now?(and the final answer is supposed to be 2)
I don't know what SAMDEB means...but

subtract Y from both sides resulting in: -2Y = -4
divide both sides by 2 gives you: y = 2

6. THANK YOU SO MUCH! (and SAMDEB is BEDMAS backwards, you use it for these kind of questions (expand first subtract and add second multiply and divide third and do brackets and exponents last)

7. Originally Posted by Arexsis
resulting in: 4y+8-"5y-1" = y-1

-5y-1... i think it's -5y-5 isn't it?

Yes it would be -5y-5.