
Exponential problem
I've got this problem:
$\displaystyle 1/4[a2e^{a/2}  4e^{a/2} + 4)] = 0.05$
and I'm supposed to solve for a. But I'm not very good with exponentials and logarithms. I start out like this:
$\displaystyle 1/4(a2e^{a/2}) e^{a/2} +1 = 0.05$
$\displaystyle 0.5a(e^{a/2}) e^{a/2} +1 = 0.05$
$\displaystyle 0.5a(e^{a/2}) e^{a/2} = 0.95$
$\displaystyle e^{a/2} (1+0.5a)= 0.95$
$\displaystyle e^{a/2} = \frac{0.95}{(1+0.5a)}$
$\displaystyle e^{a/2} = \frac{0.95}{(1+0.5a)}$
Am I right so far? And if so, where do I go next? I'd be very thankful if someone could help me out with this. And please also explain the steps.