# Math Help - Rearraniging Algebraic Equations

1. ## Rearraniging Algebraic Equations

n=(2J+1)exp(-(BJ(J+1))/KT)

Rearrange for T and J; B and K are constants.

2. $n = (2j+1)e^{-\frac{bj(j+1)}{kt}}$

$\ln{n} = \ln(2j+1) + \left(-\frac{bj(j+1)}{kt}\right)$

$\ln\left(\frac{n}{2j+1}\right) = -\frac{bj(j+1)}{kt}
$

$t = -\frac{bj(j+1)}{k\ln\left(\frac{n}{2j+1}\right)}$

I may be mistaken, but I don't think there is an elementary solution for "j".

Maybe someone more knowledgeable can show us how.