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Math Help - Rearraniging Algebraic Equations

  1. #1
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    Rearraniging Algebraic Equations

    n=(2J+1)exp(-(BJ(J+1))/KT)

    Rearrange for T and J; B and K are constants.
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  2. #2
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    n = (2j+1)e^{-\frac{bj(j+1)}{kt}}

    \ln{n} = \ln(2j+1) + \left(-\frac{bj(j+1)}{kt}\right)

    \ln\left(\frac{n}{2j+1}\right) = -\frac{bj(j+1)}{kt}<br />

    t = -\frac{bj(j+1)}{k\ln\left(\frac{n}{2j+1}\right)}

    I may be mistaken, but I don't think there is an elementary solution for "j".

    Maybe someone more knowledgeable can show us how.
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