Hi all I'm having a little trouble with a math problem,

I'm trying to find the the zeros of:

so far I have:

degree 6 so this function has 6 zeros

5, 3, or 1 positive real zeros

1 negative real zero

possible rational zeros:

using synthetic devision I found that -1 and 1 are real zeros and eliminated -5 and 5

and am left with:

I looked at the graph of this function and it only crosses the x-axis twice so I'm guessing that there are no irrational zeros and that there are two pairs of complex conjugates.

Am I right? If so how do I go about finding the complex conjugates of . If not, how do I proceed?

-thanks a bunch