Hi all I'm having a little trouble with a math problem,
I'm trying to find the the zeros of:
so far I have:
degree 6 so this function has 6 zeros
5, 3, or 1 positive real zeros
1 negative real zero
possible rational zeros:
using synthetic devision I found that -1 and 1 are real zeros and eliminated -5 and 5
and am left with:
I looked at the graph of this function and it only crosses the x-axis twice so I'm guessing that there are no irrational zeros and that there are two pairs of complex conjugates.
Am I right? If so how do I go about finding the complex conjugates of . If not, how do I proceed?
-thanks a bunch