Find the value oflog 2^1/2+1(3-2^1/2)
Hello,Joyce!
I'd like to help, but I can't read the problem . . .
Find the value oflog 2^1/2+1(3-2^1/2)
Did you even look at what showed up on the screen?
By the way, there should be no exponent in your log statement.
You probably meant something like:
If you see , do not write it as: log 2^8, which means
The "2" is a subscript, written 'below the line'.
. . You can write: log_2(8) . . . okay?
I too like Shubadeep's interpretation.
But I hope that there are typos in the original problem.
If it was: . . . . the answer is .
Otherwise, I see no point to the problem
. . other than using the Base-Change Formula
. . which could have been practiced with