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Math Help - Am I on the right track here??

  1. #1
    Junior Member
    Joined
    Sep 2008
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    48

    Question Am I on the right track here??

    A rectanglular window has a width 1' less than its length. The perimeter is 18'. Find the length and width.

    What I have so far is......

    Let x = length
    P=lw

    18=2(2x-1) -1

    am I on the right track? Thanks in advance!
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  2. #2
    Super Member
    Joined
    Jun 2008
    Posts
    792
    NO!

    Perimeter is the sum of the side lengths of a polygon, and it is not the area.

    A rectangle has 4 sides: 2 sides considered as width and 2 sides considered as lengths.

    You can then conclude that the perimeter is P = 2w + 2l

    The problem also mentions that the width is one inch less than length. From this, you can conclude that:
    w = l - 1

    Given P, solve for l, and then find w using the given relation.
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