A rectanglular window has a width 1' less than its length. The perimeter is 18'. Find the length and width.
What I have so far is......
Let x = length
P=lw
18=2(2x-1) -1
am I on the right track? Thanks in advance!
NO!
Perimeter is the sum of the side lengths of a polygon, and it is not the area.
A rectangle has 4 sides: 2 sides considered as width and 2 sides considered as lengths.
You can then conclude that the perimeter is $\displaystyle P = 2w + 2l$
The problem also mentions that the width is one inch less than length. From this, you can conclude that:
$\displaystyle w = l - 1$
Given P, solve for l, and then find w using the given relation.