A rectanglular window has a width 1' less than its length. The perimeter is 18'. Find the length and width.

What I have so far is......

Let x = length

P=lw

18=2(2x-1) -1

am I on the right track? Thanks in advance!

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- Oct 10th 2008, 12:56 PMtpomaAm I on the right track here??
A rectanglular window has a width 1' less than its length. The perimeter is 18'. Find the length and width.

What I have so far is......

Let x = length

P=lw

18=2(2x-1) -1

am I on the right track? Thanks in advance! - Oct 10th 2008, 01:02 PMChop Suey
NO!

Perimeter is the sum of the side lengths of a polygon, and it is not the area.

A rectangle has 4 sides: 2 sides considered as width and 2 sides considered as lengths.

You can then conclude that the perimeter is

The problem also mentions that the width is one inch less than length. From this, you can conclude that:

Given P, solve for l, and then find w using the given relation.